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Agricultural Energy

How to Size a Solar Irrigation Pump System: Pump, Drive and Array

On farms far from the grid, or where electricity is expensive, solar irrigation systems run a submersible or surface pump directly from PV modules. A well-sized system delivers water steadily through the sunny hours. A poorly sized one starts late in the morning, fails to reach the required flow even at noon, or stresses the drive with excessive voltage. In this article we walk through the inputs, the role of the pump drive, how the array is sized, and when a system is not a good fit, using a worked example.

System components

The inputs

Flow requirement

Daily water demand depends on the crop, the irrigated area, the method (drip, sprinkler, flood) and the season. Divide the daily demand by the number of hours of effective solar pumping to get the hourly flow. For example, if you need 120 m³ a day and expect 6 hours of effective pumping, the required average flow is 20 m³/h.

Well depth and total head

The total head the pump must overcome (total dynamic head) is the sum of:

Pump power

Pump motor power is usually given in horsepower (HP) or kW; 1 HP ≈ 0.746 kW. The hydraulic power needed to lift the water is:

P hydraulic (W) = ρ × g × Q × H, where ρ is water density (≈1,000 kg/m³), g is gravitational acceleration (9.81 m/s²), Q is flow (m³/s) and H is total head (m).

Shaft power is hydraulic power divided by pump efficiency. Always check the manufacturer's pump curve (flow vs head) when selecting a pump.

Daily irrigation hours

Sunny hours vary with the season. Irradiance is low in the morning and evening, so the pump either runs slowly or cannot lift water at all. Keep the "effective pumping hours per day" assumption realistic.

Cable length

With a submersible pump, the motor sits at the bottom of the well, so the cable between drive and motor is as long as the well depth plus the surface distance. Voltage drop on a long cable makes the motor draw more current and run hotter.

What the pump drive does

Unlike an ordinary frequency converter, a solar pump drive performs MPPT (maximum power point tracking): it finds the highest power the array can deliver at the current irradiance and sets motor speed accordingly. Speed drops as irradiance falls and rises as it increases.

One piece of physics matters a lot here: for centrifugal pumps, flow varies in proportion to speed while head varies with the square of speed. So when speed drops a little at low irradiance, the head the pump can deliver drops noticeably. In deep wells this means that below a certain speed the pump cannot bring any water to the surface.

Worked example

All figures below are example values. A real project must use the pump curve, the module and drive datasheets and site measurements.

1. Hydraulic power and pump size

2. Array power

To get enough power in the morning and evening and to cover temperature and cable losses, array power is chosen above motor power. Drive and pump manufacturers usually recommend a factor; this example uses 1.3.

3. Series string check

Example module values: Voc = 49.9 V, Vmp = 41.9 V, Voc temperature coefficient −0.27%/°C, and roughly −0.35%/°C for Vmp. Example drive: MPPT range 450–750 V DC, maximum DC input 800 V. Design temperatures: coldest ambient −10 °C, hottest cell temperature 70 °C.

Modules in seriesCold Voc (V)Hot Vmp (V)STC Vmp (V)Result
13710459545Marginal: hot Vmp very close to the MPPT minimum
14765494587Suitable
15819530629Not suitable: exceeds the 800 V limit

Choice: 14 in series × 2 in parallel = 28 modules, giving 28 × 550 = 15.4 kWp. That is 15.4 ÷ 11.19 ≈ 1.38 times motor power, slightly above the 1.3 target. Finally, check that the combined current of the two parallel strings does not exceed the drive's maximum DC input current.

4. Motor current and cable

Approximate current for a three-phase motor: I = P ÷ (√3 × U × cosφ × η). Example: 11,190 W, 400 V, cosφ = 0.85 and motor efficiency 0.88 give I ≈ 21.6 A. In a real project, use the rated current on the motor nameplate.

Voltage drop (ignoring reactance) is approximately ΔU = √3 × I × L × cosφ ÷ (κ × A), with κ ≈ 56 m/(Ω·mm²) for copper. Example: 100 m of well plus 50 m on the surface gives 150 m of cable; with a 10 mm² conductor, ΔU ≈ 1.732 × 21.6 × 150 × 0.85 ÷ (56 × 10) ≈ 8.5 V, or about 2.1% of 400 V. Check the relevant standards and the pump manufacturer's recommendation for the acceptable limit.

Fuse and cable considerations

When solar irrigation is not a good fit

Checklist

  1. Are daily water demand and effective pumping hours defined?
  2. Is total head calculated from dynamic water level, elevation and friction losses?
  3. Is the pump selected against the manufacturer's curve?
  4. Is the series module count within the drive window for cold Voc and hot Vmp?
  5. Have voltage drop and fuse ratings been checked?

Solar irrigation sizing with PVAGE

In PVAGE's agricultural energy systems module, you enter pump power (HP), well depth, daily irrigation hours and cable length (line loss), then choose a module. The result shows the module count and layout, motor current, recommended fuse and a "suitable / not suitable" assessment. The factors used in the calculation are shown on screen, and the result can be exported as a PDF.

In the proposal module, "agricultural irrigation" can be selected as the system type. For other off-grid applications, see our article on off-grid system sizing.

Explore the feature: Solar Irrigation Pump Sizing Software

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